The Textbook of Architecture

Rules · Entablatures · Spacing · Modules

Vitruvius’s half-metope

Keep every triglyph centred over a column and every intercolumniation equal, and finish the frieze at the corner with a half-metope half a module wide.

corner semi-metope = ½ M (Vitruvius); equal intercolumniations throughout

The Vitruvian solution: triglyph on the corner column axis and a half-metope (red) at the corner. Open in Models ↗

Vitruvius presents his modular Doric temple as the cure for the corner problem: by placing “semimetopes” at the outer corners he keeps the rules of the triglyph over the axis and of equal spacing, sacrificing only the Greek rule that the frieze should turn the corner on a triglyph.

This became the standard Roman and Renaissance practice, followed by Vignola and Palladio. To Greek eyes the frieze would have looked unfinished at the corner; to Roman eyes the regularity of the colonnade mattered more. The difference is a small, telling example of two attitudes to rule.

Related rules

The Doric corner conflict

A Doric frieze cannot obey all three of its rules at a corner: triglyphs over the column axes, a triglyph turning the corner, and metopes as broad as they are high. One of them must give way.

displacement of the corner triglyph = e − t⁄2 (e = half-depth of the architrave, t = triglyph width)

The Doric module

Divide the front of a Doric temple into modules; the column’s thickness is two modules, its height with the capital fourteen, the capital one, the architrave one, and the triglyphs one and a half high and one wide.

M = ½ D; column = 14 M; capital = 1 M; architrave = 1 M; triglyph = 1 × 1½ M; metope = 1½ × 1½ M

Cite this page Chris Paton, “Vitruvius’s half-metope”, The Textbook of Architecture, https://textbookofarchitecture.com/rule/vitruvius-semimetope. Text, drawings and models licensed under CC BY-NC 4.0.